A direct proof starts from the hypotheses and derives the conclusion through definitions, algebra, and previously established results. Its basic pattern is:

  1. State the hypotheses precisely.
  2. Apply definitions and valid inference rules.
  3. Reach the desired conclusion.
ExampleThe square of an odd integer is odd

Assume that nn is odd. Then n=2k+1n=2k+1 for some integer kk. Therefore

n2=(2k+1)2=4k2+4k+1=2(2k2+2k)+1.n^2=(2k+1)^2=4k^2+4k+1=2(2k^2+2k)+1.

Because 2k2+2k2k^2+2k is an integer, this has the form 2m+12m+1. Hence n2n^2 is odd.

The proof works because it uses the definition of oddness rather than relying on a numerical pattern.

ExerciseThe sum of two even integers

Prove that the sum of two even integers is even.

Solution

Let a=2ka=2k and b=2mb=2m, where k,mZk,m\in\mathbb{Z}. Then

a+b=2k+2m=2(k+m),a+b=2k+2m=2(k+m),

and k+mk+m is an integer. Thus a+ba+b is even.

ExerciseA divisibility example

Prove that n3+2nn^3+2n is divisible by 33 for every positive integer nn.

Solution

Rewrite the expression as

n3+2n=n(n21)+3n=n(n1)(n+1)+3n.n^3+2n=n(n^2-1)+3n=n(n-1)(n+1)+3n.

Among three consecutive integers, one is divisible by 33. Hence both terms on the right are divisible by 33, so the original expression is divisible by 33.

The main difficulty in a direct proof is usually choosing a representation that exposes the relevant definition or divisibility property.